. Permet-de-connaître, Tandis que dans ce cas, nous voulons calculer le nombre de mots de poids minimal dans P j (C(i)) pour chaque couple de positions (i, j) Nous avons donc dû utiliser une procédure probabiliste basée sur le problème du collectionneur de coupons (ou coupon collector problem) : la recherche de mots de poids minimal n'est arrêtée qu'à partir du moment où nous avons trouvé N mots de poids minimal et que chaque mot apparaît environ ? ln N fois (avec ? 1). Pour s'assurer d'avoir une bonne probabilité d'obtenir tous les mots de poids minimal, nous avons choisi d'utiliser cette approche avec ? = 3. Afin d'accélérer la recherche de ces mots de poids minimal

. En, nécessite environ 227 heures de calcul, tandis que le coût total de l'attaque est d'environ 280 heures. Cependant, nous avons de bonnes raisons de penser que le

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