Nous avons x k ? x k+1 , donc ? L (x k , x k+1 ) est sup-irréductible dans Con c L, Comme Con c L est booléen, ? L (x k , x k+1 ) est un atome de Con c L. Soit ? un atome de Con c L, nous avons : ? ? ? L (0, 1) = m?1 k=0 ? L (x k ,
m ? 1} tel que ? ? ? L (x k , x k+1 ) Mais ? L (x k , x k+1 ) est un atome de Con c L, d'où ? = ? L (x k , x k+1 ) Donc Con c f est surjective ,
nous pouvons supposer que 0 et 1 sont dans C) Soit f : C ? K l'injection canonique Supposons que g : C ? ? K ? soit un relèvement de Con c f dans V 2 Comme f est injective, g est aussi injectiveC ? ) = n + 1. D'où n ? lh(K ? ) ? lh(C ? ) = n + 1 ; une contradiction ,
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