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On factorization of separating maps on noncommutative $L^p$-spaces

Abstract : For any semifinite von Neumann algebra ${\mathcal M}$ and any $1\leq p<\infty$, we introduce a natutal $S^1$-valued noncommutative $L^p$-space $L^p({\mathcal M};S^1)$. We say that a bounded map $T\colon L^p({\mathcal M})\to L^p({\mathcal N})$ is $S^1$-bounded (resp. $S^1$-contractive) if $T\otimes I_{S^1}$ extends to a bounded (resp. contractive) map $T\overline{\otimes} I_{S^1}$ from $ L^p({\mathcal M};S^1)$ into $L^p({\mathcal N};S^1)$. We show that any completely positive map is $S^1$-bounded, with $\Vert T\overline{\otimes} I_{S^1}\Vert =\Vert T\Vert$. We use the above as a tool to investigate the separating maps $T\colon L^p({\mathcal M})\to L^p({\mathcal N})$ which admit a direct Yeadon type factorization, that is, maps for which there exist a $w^*$-continuous $*$-homomorphism $J\colon{\mathcal M}\to{\mathcal N}$, a partial isometry $w\in{\mathcal N}$ and a positive operator $B$ affiliated with ${\mathcal N}$ such that $w^*w=J(1)=s(B)$, $B$ commutes with the range of $J$, and $T(x)=wBJ(x)$ for any $x\in {\mathcal M}\cap L^p({\mathcal M})$. Given a separating isometry $T\colon L^p({\mathcal M})\to L^p({\mathcal N})$, we show that $T$ is $S^1$-contractive if and only if it admits a direct Yeadon type factorization. We further show that if $p\not=2$, the above holds true if and only if $T$ is completely contractive.
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Contributor : Christian Le Merdy Connect in order to contact the contributor
Submitted on : Friday, January 14, 2022 - 10:01:12 AM
Last modification on : Wednesday, January 19, 2022 - 4:33:09 PM
Long-term archiving on: : Friday, April 15, 2022 - 6:25:02 PM


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  • HAL Id : hal-03525811, version 1
  • ARXIV : 2007.04577



Christian Le Merdy, Safoura Zadeh. On factorization of separating maps on noncommutative $L^p$-spaces. Indiana University Mathematics Journal, Indiana University Mathematics Journal, 2022. ⟨hal-03525811⟩



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